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- From: clamage@Eng.Sun.COM (Steve Clamage)
- Message-ID: <4h4jl4$2iq@engnews1.Eng.Sun.COM>
- X-Original-Date: 29 Feb 1996 16:18:44 GMT
- Path: in1.uu.net!bounce-back
- Date: 01 Mar 96 13:43:43 GMT
- Approved: fjh@cs.mu.oz.au
- Return-Path: <daemon@meeker.UCAR.EDU>
- Newsgroups: comp.std.c++
- Subject: Re: Namespaces within class definition???
- Organization: Sun Microsystems Inc.
- References: <4h2mlp$s3c@nnrp1.news.primenet.com>
- Reply-To: clamage@Eng.Sun.COM
- X-Auth: PGPMoose V1.1 PGP comp.std.c++
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-
- In article s3c@nnrp1.news.primenet.com, kj7bg@primenet.com (Bob White) writes:
- >... I tried the following and it seems to work:
- >
- >typedef std::string XyzString;
- >class xyz : public XyzString { }
- >
- >So I will use it until Borland and Microsoft allow me the more
- >straight forward way. Also, I am using the "string" class as defined by one
- >version of the C++ standard which was put in the "std" namespace. I thought
- >this was what the current standard required!
-
- Yes. The draft standard defines a string class called "string", and
- all library elements are in the "std" namespace. You have basically
- three ways to access names in the standard library:
- 1. Explicit qualification:
- std::string MyString;
- 2. A using-declaration:
- using std::string;
- string MyString;
- 3. A using-directive:
- using namespace std;
- string MyString;
-
- The using-declaration (#2) places the specified name in the current scope
- having its original declaration.
-
- The using-directive (#3) makes all names from the namespace visible from
- the current scope, which is subtly different from placing those names IN
- the current scope. (And subtly different from placing them in a notional
- surrounding scope.) See Stroustrup's "Design and Evolution of C++" for
- more details.
-
- Your typedef is a variation of #1.
-
- ---
- Steve Clamage, stephen.clamage@eng.sun.com
- ---
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